Miten muunnetaan y = 2y ^ 2 + 3x ^ 2-2xy polaariseksi yhtälöksi?

Vastaus:

# R = sintheta / (2sin ^ 2theta + 3cos ^ 2theta-sin (2theta)) #

Selitys:

Tätä varten tarvitsemme:

# X = rcostheta #

# Y = rsintheta #

# Rsintheta = 2 (rsintheta) ^ 2 + 3 (rcostheta) ^ 2-2 (rcostheta) (rsintheta) #

# Rsintheta = 2r ^ 2sin ^ 2theta + 3r ^ 2cos ^ 2theta-2h ^ 2costhetasintheta #

# Sintheta = 2rsin ^ 2theta + 3rcos ^ 2theta-2rcosthetasintheta #

# Sintheta = 2rsin ^ 2theta + 3rcos ^ 2theta-RSIN (2theta) #

# Sintheta = r (2sin ^ 2theta + 3cos ^ 2theta-sin (2theta)) #

# R = sintheta / (2sin ^ 2theta + 3cos ^ 2theta-sin (2theta)) #